A resistor of 4 k Ω with tolerance 10% is connected in parallel with a resistor of 6 k Ω with tolerance 10%. The tolerance of the parallel combination is nearly

Question

A resistor of 4 k Ω with tolerance 10% is connected in parallel with a resistor of 6 k Ω with tolerance 10%. The tolerance of the parallel combination is nearly, 10%, 20%, 30%, 40%

MARKS App · Accepted Answer

R s = R 1 R 2 R 1 + R 2 , ∆ R s R s × 100 = ∆ R 1 R 1 × 100 + ∆ R 2 R 2 × 100 + ∆ ( R 1 + R 2 ) R 1 + R 2 ×​ 100 Now, ∆ R 1 = 10 100 × 4 k Ω =0.4k Ω , Δ R 2 = 10 100 × 6 k Ω = 0.6 k Ω Again, ∆ R s R s × 100 = 0.4 4 × 100 + 0.6 6 × 100 + 0.4 + 0.6 10 × 100 = 10 + 10 + 10 = 30

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