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Question: Answered & Verified by Expert
A rigid square loop of side a and carrying current I2 is lying on a horizontal surface near a long current I1 carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be:
PhysicsMagnetic Effects of CurrentJEE MainJEE Main 2019 (09 Apr Shift 1)
Options:
  • A Attractive and equal to μ0I1I23π
  • B Repulsive and equal to μ0I1I24π
  • C Repulsive and equal to μ0I1I22π
  • D Zero
Solution:
2461 Upvotes Verified Answer
The correct answer is: Repulsive and equal to μ0I1I24π

Force on segment 1-2 and 3-4 will get cancel out.
Force on segment 4-1,
F1=μ0I1I22πa×a toward Right
Force on segment 2-3:
F2=μ0I1I22π(2a)×a  toward left
Net force on loop:
Fnet=F1-F2 toward Right
=μ0I1I22π-μ0I1I24π
=μ0I1I24π toward Right or repulsive

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