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Question: Answered & Verified by Expert
A rigid square loop of side ' \( \mathrm{a} \) ' and carrying current \( \mathrm{I}_{2} \) is lying on a horizontal surface near a long current \( \mathrm{I}_{1} \) carrying wire in
the same plane as shown in figure. The net force on the loop due to the wire will be:
PhysicsMagnetic Effects of CurrentJEE Main
Options:
  • A Attractive and equal to \( \frac{\mu_{0} \mathrm{I}_{1} \mathrm{I}_{2}}{3 \pi} \)
  • B Repulsive and equal to \( \frac{\mu_{0} I_{1} I_{2}}{4 \pi} \)
  • C Repulsive and equal to \( \frac{\mu_{0} I_{1} I_{2}}{2 \pi} \)
  • D Zero
Solution:
2932 Upvotes Verified Answer
The correct answer is: Repulsive and equal to \( \frac{\mu_{0} I_{1} I_{2}}{4 \pi} \)

Force on segment 1-2 and 3-4 will get cancel out.
Force on segment 4-1,
F1=μ0I1I22πa×a toward Right
Force on segment 2-3:
F2=μ0I1I22π(2a)×a  toward left
Net force on loop:
Fnet=F1-F2 toward Right
=μ0I1I22π-μ0I1I24π
=μ0I1I24π toward Right or repulsive

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