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A ring and a disc have same mass and same radius. The ratio of moment of inertia
of a ring about a tangent in its plane to that of the disc about its diameter is
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of a ring about a tangent in its plane to that of the disc about its diameter is
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The correct answer is:
$6: 1$
Moment of inertia of a ring about a tangent in its plane is given by $I=\frac{3}{2} M R^{2}$
Moment of inertia of a disc about its diameter is given by $I^{\prime}=\frac{1}{4} M R^{2}$
$\therefore \frac{I}{I^{\prime}}=6$
Moment of inertia of a disc about its diameter is given by $I^{\prime}=\frac{1}{4} M R^{2}$
$\therefore \frac{I}{I^{\prime}}=6$
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