A ring of mass 5 kg sliding on a frictionless vertical rod connected by a block B of mass 10 kg by the help of a massless string. Then at the equilibrium of the system the value of θ is

Question

A ring of mass 5 kg sliding on a frictionless vertical rod connected by a block B of mass 10 kg by the help of a massless string. Then at the equilibrium of the system the value of θ is, 30 °, 60 °, 90 °, 0 °

MARKS App · Accepted Answer

For ring, From force diagram of ring, T cos ⁡ θ = m 1 g ......(i) For block B m g = T ........ (ii) T cos ⁡ θ = m 1 g m g cos ⁡ θ = m 1 g ∴ cos ⁡ θ = m 1 m = 5 10 = 1 2 ⇒ θ = 60 °

Search any question & find its solution

Looking for more such questions to practice?