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A rubber ball be taken in a deep sea so that its volume is decreased by $x \%$. The
bulk modulus of rubber is 'K' and density of sea water is ' $\varrho$ '. The depth to whÃch a rubber ball is taken is proportional to $(\mathrm{g}=$ acceleration due to gravity)
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bulk modulus of rubber is 'K' and density of sea water is ' $\varrho$ '. The depth to whÃch a rubber ball is taken is proportional to $(\mathrm{g}=$ acceleration due to gravity)
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Verified Answer
The correct answer is:
$\frac{\mathrm{Kx}}{\mathrm{eg}}$
$B=-\frac{\Delta p}{\Delta v / v}$
$\frac{\Delta v}{v}=\frac{x}{100}...(1)$
$\Delta p=\rho g h$
$\frac{\rho g h}{x / 100}$
$h \propto \frac{k x}{\rho g}$
$\frac{\Delta v}{v}=\frac{x}{100}...(1)$
$\Delta p=\rho g h$
$\frac{\rho g h}{x / 100}$
$h \propto \frac{k x}{\rho g}$
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