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A rubber ball filled with water, having a small hole is used as the bob of a simple pendulum. The time period of such a pendulum
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first increases and then decreases, finally having same value as at the beginning
$\text { From } T=2 \pi \sqrt{\frac{L}{g}}$
The effective length increases due to this flow of water. Therefore, $\mathrm{T}$ increases. As the water flows out, the length decreases and becomes equal to the original length. Hence, the time period becomes equal to the value at the beginning.
The effective length increases due to this flow of water. Therefore, $\mathrm{T}$ increases. As the water flows out, the length decreases and becomes equal to the original length. Hence, the time period becomes equal to the value at the beginning.
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