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A rubber pipe of density $1.5 \times 10^3 \mathrm{~N} / \mathrm{m}^2$ and Young's modulus $5 \times 10^6 \mathrm{~N} / \mathrm{m}^2$ is suspended from the roof. The length of the pipe is $8 \mathrm{~m}$. What will be the change in length due to its own weight
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The correct answer is:
$9.6 \times 10^{-2} \mathrm{~m}$
$l=\frac{L^2 d g}{2 T}=\frac{(8)^2 \times 1.5 \times 10^3 \times 10}{2 \times 5 \times 10^6}=9.6 \times 10^{-2} \mathrm{~m}$
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