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Question: Answered & Verified by Expert
A rubber pipe of density $1.5 \times 10^3 \mathrm{~N} / \mathrm{m}^2$ and Young's modulus $5 \times 10^6 \mathrm{~N} / \mathrm{m}^2$ is suspended from the roof. The length of the pipe is $8 \mathrm{~m}$. What will be the change in length due to its own weight
PhysicsMechanical Properties of SolidsJEE Main
Options:
  • A $9.6 \mathrm{~m}$
  • B $9.6 \times 10^3 \mathrm{~m}$
  • C $19.2 \times 10^{-2} \mathrm{~m}$
  • D $9.6 \times 10^{-2} \mathrm{~m}$
Solution:
2399 Upvotes Verified Answer
The correct answer is: $9.6 \times 10^{-2} \mathrm{~m}$
$l=\frac{L^2 d g}{2 T}=\frac{(8)^2 \times 1.5 \times 10^3 \times 10}{2 \times 5 \times 10^6}=9.6 \times 10^{-2} \mathrm{~m}$

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