A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1 m/s so as to have same K.E. as that of the boy. The original speed of the man will be

Question

A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1 m/s so as to have same K.E. as that of the boy. The original speed of the man will be, 2 m/s, 2 - 1 m/s, 1 ( 2 - 1 ) m/s, 1 2 m/s

MARKS App · Accepted Answer

Let m = mass of boy, M = mass of man v = velocity of boy, V = velocity of man 1 2 M V 2 = 1 2 [ 1 2 m v 2 ] … (i) 1 2 M ( V + 1 ) 2 = 1 [ 1 2 m v 2 ] …(ii) Putting m = M 2 and solving V = 1 2 − 1

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