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A sample has half life of $10^{33}$ year. If initial number of nuclei of the sample is $26 \times 10^{34}$. Then find out the number of nuclei decayed in 1 year.
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$182$
$\begin{aligned} & \text { }-\frac{d N}{d t}=\lambda N \\ & -d N=\frac{\ln 2}{T_{1 / 2}} \times N \times d t=\frac{0.7}{10^{33}} \times 26 \times 10^{34} \times 1=182 .\end{aligned}$
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