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Question: Answered & Verified by Expert
A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal energy of the gas along the path ca is -180 J. The gas absorbs 250 J of heat along the path ab and 60 J along the path bc . The work done by the gas along the path abc is:
PhysicsThermodynamicsJEE MainJEE Main 2019 (12 Apr Shift 1)
Options:
  • A 130 J
  • B 100 J
  • C 120 J
  • D 140 J
Solution:
2635 Upvotes Verified Answer
The correct answer is: 130 J
In a cyclic process, ΔU=0
From 1st law of thermodynamics
Q=ΔU+W
Q=W
Qab+Qbc+Qca=Wabc+Wca
Wabc=Qab+Qbc+Qca-Wca
Wabc=Qab+Qbc+Uca
Wabc=250+60-180=130 J

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