A sample of HI (g) is placed in flask at a pressure of $0.2$ atm. At equilibrium, the partial pressure of HI (g) is $0.04$ atm. What is $K_p$ for the given equilibrium ?

Question

A sample of HI (g) is placed in flask at a pressure of $0.2$ atm. At equilibrium, the partial pressure of HI (g) is $0.04$ atm. What is $K_p$ for the given equilibrium ?,

MARKS App · Accepted Answer

$\begin{array}{lll}\text { At eqm, } 0.04 \mathrm{~atm} & 0.16 / 2 \mathrm{~atm} & 0.16 / 2 \mathrm{~atm} \ & =0.08 \mathrm{~atm} & =0.08 \mathrm{~atm}\end{array}$ (Decrease in the pressure of $\mathrm{HI}=0.2-0.04=0.16 \mathrm{~atm}$.) $\therefore \mathrm{K}_{\mathrm{p}}=\frac{\mathrm{p}_{\mathrm{H}_2} \times \mathrm{p}_{\mathrm{I}_2}}{\mathrm{p}_{\mathrm{HI}}^2}=\frac{0.08 \mathrm{~atm} \times 0.08 \mathrm{~atm}}{(0.04 \mathrm{~atm})^2}=4.0$

Search any question & find its solution

Looking for more such questions to practice?