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Question: Answered & Verified by Expert
A satellite is launched into a circular orbit, R4 above the surface of the earth. The time period of revolution is T=2πn32Rg. Where R is the radius of the earth and g is the acceleration due to gravity. Then what is value on n?
PhysicsGravitationJEE Main
Solution:
2955 Upvotes Verified Answer
The correct answer is: 1.25
T=2πr32gR2  where = R h

Then,  T=2πR+hRR+hg

Here, h=R4

T=2πR+R4RR+R4g=2π1.2532Rg

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