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Question: Answered & Verified by Expert
A satellite of mass m is launched vertically upwards with an initial speed u from the surface of the earth. After it reaches height R ( R= radius of the earth), it ejects a rocket of mass m10 so that subsequently the satellite moves in a circular orbit. The kinetic energy of the rocket is ( G is the gravitational constant; M is the mass of the earth):
PhysicsGravitationNEET
Options:
  • A m20u2+113200GMR
  • B 5mu2-119200GMR
  • C 3m8u+5GM6R2
  • D m20u-2GM3R2
Solution:
2793 Upvotes Verified Answer
The correct answer is: 5mu2-119200GMR
-GMemR+12mu2=-GMem2R+12mv2



v=u2-GMeR



M10vr=Mu2-GMeR
Kinetic energy =12M10VT2+Vr2=M2081GM2R+100u2-100GMR
= M 20 100 u 2 119GM 2R
=5mu2-119GM200R

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