A second's pendulum clock having steel wire is calibrated at 20 ° C . When the temperature is increased to 30 ° C , how much times does the clock lose or gain in the week? α s t e e l = 1 .2 × 10 - 5 ° C - 1

Question

A second's pendulum clock having steel wire is calibrated at 20 ° C . When the temperature is increased to 30 ° C , how much times does the clock lose or gain in the week? α s t e e l = 1 .2 × 10 - 5 ° C - 1, 0.3628 s, 3.626 s, 362.8 s, 36.28 s

MARKS App · Accepted Answer

T = 2 π l g ΔT T = 1 2 Δl l ΔT T = 1 2 αΔθ ΔT = 1 2 αΔθT ΔT = 1 2 1 .2 × 10 - 5 30 - 20 3600 × 24 × 7 ΔT = 36 .28 s

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