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Question: Answered & Verified by Expert
A section of fixed smooth circular track of radius R in vertical plane is shown in the figure. A block is released from position A and leaves the track at B . The radius of curvature of its trajectory when it just leaves the track at B is-

PhysicsLaws of MotionNEET
Options:
  • A R
  • B R/4
  • C R/2
  • D none
Solution:
2292 Upvotes Verified Answer
The correct answer is: R/2


In figure

OC=R cos53°=3R5; OE=R cos37°=4R5

So CE=R5

From A to B,

12mv2=mgR5 [Energy conservation]

v=2gR5

Let radius of curvature at B is r

g cos37°=v2r

r=v2g cos37°=2gR5×10×4/5=R2

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