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A segment of DNA has 120 adenine and 120 cytosine bases. The total number of nucleotides present in the segment is
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480
According to Chargaff's rules, the amount of adenine is always equal to that of thymine, and the amount of guanine is always equal to that of cytosine.
$\begin{aligned} \mathrm{A} & =\mathrm{T}(120) \\ \mathrm{G} & =\mathrm{C}(120)\end{aligned}$
The total number of nucleotides would be $120 \times 4=480$.
$\begin{aligned} \mathrm{A} & =\mathrm{T}(120) \\ \mathrm{G} & =\mathrm{C}(120)\end{aligned}$
The total number of nucleotides would be $120 \times 4=480$.
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