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A self-fertilizing trihybrid plant forms:
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8 different gametes and 64 different zygotes
The genotype of trihybrid would be $\mathrm{AaBbCc}$.
Number of gametes $=$ (no. of genes studied) ${ }^n$
Where $n=$ no. of heterozygous alleles
Thus, Number of gametes $=(2)^3=8$
No. of Zygotes $=(2)^{2 \mathrm{n}}=(2)^{2 \times 3}=(2)^6$ $=64$
Number of gametes $=$ (no. of genes studied) ${ }^n$
Where $n=$ no. of heterozygous alleles
Thus, Number of gametes $=(2)^3=8$
No. of Zygotes $=(2)^{2 \mathrm{n}}=(2)^{2 \times 3}=(2)^6$ $=64$
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