A series $ L C R $ circuit is connected to an ac voltage source. When $ L $ is removed from the circuit, the phase difference between current and voltage is $ \frac{\pi}{3} $. If instead $ C $ is removed from the circuit, the phase difference is again $ \frac{\pi}{3} $ between current and voltage. The power factor of the circuit is:

Question

A series $ L C R $ circuit is connected to an ac voltage source. When $ L $ is removed from the circuit, the phase difference between current and voltage is $ \frac{\pi}{3} $. If instead $ C $ is removed from the circuit, the phase difference is again $ \frac{\pi}{3} $ between current and voltage. The power factor of the circuit is:, $ 0.5 $, $ 1.0 $, $ -1.0 $, zero

MARKS App · Accepted Answer

When L removed tan ϕ = X C R When L removed tan ϕ = X L R X C R = X L R ⇒ Resonance Z = R cos ϕ = R Z = R R = 1

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