A set of 56 tuning forks are arranged in series of increasing frequencies. If each fork gives 4 beats with preceding one and the frequency of the last is twice than that of first, then frequency of the first fork is

Question

A set of 56 tuning forks are arranged in series of increasing frequencies. If each fork gives 4 beats with preceding one and the frequency of the last is twice than that of first, then frequency of the first fork is, 110 Hz, 220 Hz, 224 Hz, 448 Hz

MARKS App · Accepted Answer

n 56 = n 1 + 56 - 1 4 Also, n 56 = 2 n 1 ∴ 2 n 1 = n 1 + 55 × 4 ∴ n 1 = 220 Hz

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