A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A , B and C . The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A = 100 g mol - 1 ; B = 200 g mol - 1 ; C = 10 , 000 g mol - 1 ]

Question

A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A , B and C . The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A = 100 g mol - 1 ; B = 200 g mol - 1 ; C = 10 , 000 g mol - 1 ], B > C > A, C > B > A, A > B > C, A > C > B

MARKS App · Accepted Answer

Number of moles = wt gm MW = 10 MW Relative lowering in vapour pressure depends on no. of mole of solute greater the no. of moleof solute greater in RLVP and smaller will be vapour pressure. So order of vapour pressure is A > B > C .

Search any question & find its solution

Looking for more such questions to practice?