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A shell of mass $200 \mathrm{gm}$ is ejected from a gun of mass $4 \mathrm{~kg}$ by an explosion that generates $1.05 \mathrm{~kJ}$ of energy. The initial velocity of the shell is
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The correct answer is:
$100 \mathrm{~ms}^{-1}$
Let the initial velocity of the shell be $\mathrm{v}$, then velocity of gun is $\left(\frac{0.2 v}{4}\right)$. (from
conservation of linar moment)
Now $1.05 \times 10^3=\frac{1}{2}(0.2) v^2+\frac{1}{2}(4)\left(\frac{0.2 v}{4}\right)^2 \Rightarrow v=100 \mathrm{~m} / \mathrm{s}$
conservation of linar moment)
Now $1.05 \times 10^3=\frac{1}{2}(0.2) v^2+\frac{1}{2}(4)\left(\frac{0.2 v}{4}\right)^2 \Rightarrow v=100 \mathrm{~m} / \mathrm{s}$
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