A shell of mass m is at rest initially. It explodes into three fragments having mass in the ratio 2 : 2 : 1 . If the fragments having equal mass fly off along mutually perpendicular directions with speed v , the speed of the third (lighter) fragment is:

Question

A shell of mass m is at rest initially. It explodes into three fragments having mass in the ratio 2 : 2 : 1 . If the fragments having equal mass fly off along mutually perpendicular directions with speed v , the speed of the third (lighter) fragment is:, 2 v, 2 2 v, 3 2 v, v

MARKS App · Accepted Answer

The speed of the third particle will be along angle bisector of the other two velocities. Applying the conservation of momentum, m v ' = 2 m v cos 45 ° + 2 m v cos 45 ° ⇒ v ' = 2 2 v

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