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Question: Answered & Verified by Expert
A shopkeeper has \( 10 \) copies each of nine different books, then the number of ways in which atleast one book can be selected is
MathematicsPermutation CombinationJEE Main
Options:
  • A \( 9^{11}-1 \)
  • B \( 10^{10}-1 \)
  • C \( 11^{9}-1 \)
  • D \( 10^{9} \)
Solution:
1288 Upvotes Verified Answer
The correct answer is: \( 11^{9}-1 \)
B 1 10 B 2 10 B 3 10 .. B 9 10
1st kind of book can be selected in 10+1 ways.
Similarly each kind of book can be selected in 10+1 ways.
So, selection of atleast one book =10+110+1..10+1times-1
=119-1

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