A silver chromate solution at 298 K has its K sp value = 1.1 × 10 − 12 . Determine the solubility of the solution in mol L − 1

Question

A silver chromate solution at 298 K has its K sp value = 1.1 × 10 − 12 . Determine the solubility of the solution in mol L − 1, 6 . 5 × 10 - 5, 2 . 4 × 10 - 2, 3 . 6 × 10 - 3, 8 . 9 × 10 - 4

MARKS App · Accepted Answer

Ag 2 CrO 4 s ⇌ 2Ag + 2s + CrO 4 2 − s ; K sp = 1 .1 × 10 − 12 ​ K sp = Ag + 2 · CrO 4 2 - K sp = [ 2 s ] 2 . s = 4 s 3 s 3 = K sp 4 = 1.1 × 10 − 12 4 ​ s = 275 × 10 − 15 3 ​ = 6.5 × 10 − 5 mol L − 1 ⇒ s = 6.53 × 10 − 5

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