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A silver ingot weighing $2.1 \mathrm{~kg}$ is held by a string so as to be completely immersed in a liquid of relative density 0.8 . The relative density of silver is 10.5 . The tension in the string in $\mathrm{kg}-\mathrm{wt}$ is
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The correct answer is:
1.94
Apparent weight $=V(\rho-\sigma) g=\frac{M}{\rho}(\rho-\sigma) g$
$=M\left(1-\frac{\sigma}{\rho}\right) g=2.1\left(1-\frac{0.8}{10.5}\right) g=1.94 g_N$
$=1.94 \mathrm{Kg}$-wt
$=M\left(1-\frac{\sigma}{\rho}\right) g=2.1\left(1-\frac{0.8}{10.5}\right) g=1.94 g_N$
$=1.94 \mathrm{Kg}$-wt
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