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A simple harmonic motion is represented by $F(t)=10 \sin (20 t+0.5)$. The amplitude of the S.H.M. is
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Verified Answer
The correct answer is:
$a=10$
Given,
$F(t)=10 \sin (20 t+0.5)$
Equation of $\mathrm{SHM}$
$y=a \sin (\omega t+\varphi)$
on comparing,
$a=$ Amplitude $=10$
$F(t)=10 \sin (20 t+0.5)$
Equation of $\mathrm{SHM}$
$y=a \sin (\omega t+\varphi)$
on comparing,
$a=$ Amplitude $=10$
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