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Question: Answered & Verified by Expert
A simple harmonic oscillator has amplitude A angular frequency ω and mass m. Then average kinetic energy in one time period is
PhysicsOscillationsNEET
Options:
  • A 12mω2A2
  • B 14mω2A2
  • C mω2A2
  • D zero
Solution:
2277 Upvotes Verified Answer
The correct answer is: 14mω2A2
Let displacement be x=Asinωt+ϕ

Kinetic energy, K=12mω2A2cos2ωt+ϕ

As the average value of cos2ωt+ϕ over a cycle is 12 .

Therefore average kinetic energy is Kav=14mω2A2

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