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A simple harmonic oscillator has an amplitude A and time period 6π second. Assuming the oscillation starts from its mean position, the time required by it to travel from x=A to x=32A will be πx s, where x=_______.
PhysicsOscillationsJEE MainJEE Main 2024 (29 Jan Shift 2)
Solution:
2712 Upvotes Verified Answer
The correct answer is: 2

From phasor diagram particle has to move from P to Q in a circle of radius equal to amplitude of SHM.

cosϕ=3 A2 A=32

ϕ=π6

Now, π6=ωt

π6=2πTt

π6=2π6πt

t=π2

So, x=2

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