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Question: Answered & Verified by Expert
A simple harmonic progressive wave is represented as $Y=A \sin 2 \pi\left(n t-\frac{x}{\lambda}\right) \mathrm{cm}$. If the maximum particle velocity is four times the wave velocity, then the wavelength of the wave is
PhysicsOscillationsMHT CETMHT CET 2020 (15 Oct Shift 2)
Options:
  • A $\frac{\pi \mathrm{A}}{4}$
  • B $4 \pi \mathrm{A}$
  • C $2 \pi \mathrm{A}$
  • D $\frac{\pi \mathrm{A}}{2}$
Solution:
1635 Upvotes Verified Answer
The correct answer is: $\frac{\pi \mathrm{A}}{2}$
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