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Question: Answered & Verified by Expert
A simple pendulum m long swings with an amplitude of 0.2 m . What is its acceleration at the ends of its path ? g=10 m s-2
PhysicsOscillationsNEET
Options:
  • A zero
  • B 10 m s-2
  • C 0.5m s-2
  • D 2.5m s-2
Solution:
2075 Upvotes Verified Answer
The correct answer is: 0.5m s-2


T=mgcosθ

Fnet=mg sin θ 

and acceleration =gsinθ=gtanθ as angle is very small sinθ=tanθ

anet=10×0.24=0.5 m s-2

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