A simple pendulum of length 1 m has a wooden bob of mass 1 kg . It is struck by a bullet of mass 10 - 2 kg moving with a speed of 2 × 10 2 m s - 1 . The bullet gets embedded into the bob. The height to which the bob rises before swinging back is. (use g = 10 m s - 2 )

Question

A simple pendulum of length 1 m has a wooden bob of mass 1 kg . It is struck by a bullet of mass 10 - 2 kg moving with a speed of 2 × 10 2 m s - 1 . The bullet gets embedded into the bob. The height to which the bob rises before swinging back is. (use g = 10 m s - 2 ), 0 . 30 m, 0 . 20 m, 0 . 35 m, 0 . 40 m

MARKS App · Accepted Answer

Linear momentum will be conserved, therefore m u = M + m V ⇒ 10 − 2 × 2 × 10 2 ≅ 1 × V ⇒ V ≅ 2 m s - 1 Again from energy conservation, we get height achieved, h = V 2 2 g = 0 .2 m .

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