A single slit of width 0 . 1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0 . 5 m from the slit. The distance of the third dark band from the central bright band is:

Question

A single slit of width 0 . 1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0 . 5 m from the slit. The distance of the third dark band from the central bright band is:, 9 mm, 3 mm, 4.5 mm, 1.5 mm

MARKS App · Accepted Answer

a = 0.1 mm = 10 - 4 m λ = 6000 × 10 - 10 = 6 × 10 - 7 m D = 0.5 m For 3 r d dark a sin ⁡ θ = 3 λ sin ⁡ θ = 3 λ a = x D x = 3 λ D a = 3 × 6 × 10 - 7 × 0.5 10 - 4 = 9 mm

Search any question & find its solution

Looking for more such questions to practice?