A skater of mass m standing on ice throws a stone of mass M = 2 m with a velocity of v = 5 m/s in horizontal direction. If the coefficient of friction between the skater and the ice is 0.5 , find the distance over which the skater will move. (take g = 10 m s - 2 )

Question

A skater of mass m standing on ice throws a stone of mass M = 2 m with a velocity of v = 5 m/s in horizontal direction. If the coefficient of friction between the skater and the ice is 0.5 , find the distance over which the skater will move. (take g = 10 m s - 2 ), 20 m, 15 m, 10 m, 5 m

MARKS App · Accepted Answer

By momentum conservation, 2 m × 5 = m × V ' So, V ' = 10 m / sec Let skater stops after travelling distance s. So, 0 2 = 10 2 - 2 × μ × g × s s = 10 m

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