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A slit of size $0.15 \mathrm{~cm}$ is placed at $2.1 \mathrm{~m}$ from a screen. On illuminated it by a light of wavelength $5 \times 10^{-5}$ $\mathrm{cm}$. The width of central maxima will be
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$1.4 \mathrm{~mm}$
Width of central maxima $=\frac{2 \lambda D}{d}$
$=\frac{2 \times 2.1 \times 5 \times 10^{-7}}{0.15 \times 10^{-2}}=1.4 \times 10^{-3} \mathrm{~m}=1.4 \mathrm{~mm}$
$=\frac{2 \times 2.1 \times 5 \times 10^{-7}}{0.15 \times 10^{-2}}=1.4 \times 10^{-3} \mathrm{~m}=1.4 \mathrm{~mm}$
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