Search any question & find its solution
Question:
Answered & Verified by Expert
A slit of width 'a' is illuminated with a monochromatic light of wavelength $\lambda$ from a distant source and the diffraction pattern is observed on a screen placed at a distance 'D' from the slit. To increase the width of the central maximum one should
Options:
Solution:
2883 Upvotes
Verified Answer
The correct answer is:
decrease a
By the theory of diffraction at a single slit, the width of the central maximum is given by
$\begin{array}{l}
\mathrm{W}=\frac{2 \mathrm{D} \lambda}{\mathrm{a}} \Rightarrow \mathrm{W} \propto \mathrm{D} \\
\mathrm{W} \propto \lambda \text { and } \mathrm{W} \propto \frac{1}{\mathrm{a}}
\end{array}$
Therefore, to increase the width of the central maximum a should be decreased.
$\begin{array}{l}
\mathrm{W}=\frac{2 \mathrm{D} \lambda}{\mathrm{a}} \Rightarrow \mathrm{W} \propto \mathrm{D} \\
\mathrm{W} \propto \lambda \text { and } \mathrm{W} \propto \frac{1}{\mathrm{a}}
\end{array}$
Therefore, to increase the width of the central maximum a should be decreased.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.