Search any question & find its solution
Question:
Answered & Verified by Expert
A small asteroid is orbiting around the sun in a circular orbit of radius $\mathrm{r}_{0}$ with speed $\mathrm{V}_{0}$. A rocket is launched from the asteroid with speed $\mathrm{V}=\alpha \mathrm{V}_{0}$, where $\mathrm{V}$ is the speed relative to the sun. The highest value of $\alpha$ for which the rocket will remain bound to the solar system is (ignoring gravity due to the asteroid and effects of other planets) -
Options:
Solution:
1337 Upvotes
Verified Answer
The correct answer is:
1
$\begin{array}{l}
\text { B.E }=\frac{G m M}{2 R} \\
\text { B.E }=\frac{1}{2} m v_{0}^{2} \\
\text { so, } \alpha=1
\end{array}$
\text { B.E }=\frac{G m M}{2 R} \\
\text { B.E }=\frac{1}{2} m v_{0}^{2} \\
\text { so, } \alpha=1
\end{array}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.