Search any question & find its solution
Question:
Answered & Verified by Expert
A small block of mass $\mathrm{m}$ is kept on a rough inclined surface of inclination $\theta$ fixed in a elevator. The elevator goes up with a uniform velocity $\mathrm{v}$ and the block does not slide on the wedge. The work done by the force of friction on the block in time t will be:
Options:
Solution:
1279 Upvotes
Verified Answer
The correct answer is:
$\mathrm{mgvt} \sin ^{2} \theta$
\(\mathrm{W}_{\mathrm{f}}=\mathrm{f} \sin \theta \mathrm{S}\)
\(=(\mathrm{mg} \sin \theta)(\sin \theta)(\mathrm{vt})\)
\(=\mathrm{mg} \sin ^{2} \theta \mathrm{vt}\)
\(=(\mathrm{mg} \sin \theta)(\sin \theta)(\mathrm{vt})\)
\(=\mathrm{mg} \sin ^{2} \theta \mathrm{vt}\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.