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Question: Answered & Verified by Expert
A small body of mass $0.10 \mathrm{~kg}$ is executing S.H.M. of amplitude $1.0 \mathrm{~m}$ and period $0.20 \mathrm{sec}$. The maximum force acting on it is
PhysicsOscillationsJEE Main
Options:
  • A $98.596 \mathrm{~N}$
  • B $985.96 \mathrm{~N}$
  • C $100.2 \mathrm{~N}$
  • D $76.23 \mathrm{~N}$
Solution:
1953 Upvotes Verified Answer
The correct answer is: $98.596 \mathrm{~N}$
Maximum acceleration
$\begin{gathered}A_{\max }=a \omega^2=\frac{a \times 4 \pi^2}{T^2}=\frac{1 \times 4 \times(3.14)^2}{0.2 \times 0.2} \\ F_{\max }=m \times A_{\max }=\frac{0.1 \times 4 \times(3.14)^2}{0.2 \times 0.2}=98.596 \mathrm{~N}\end{gathered}$

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