A small circular loop of conducting wire has radius a and carries current I . It is placed in a uniform magnetic field B perpendicular to its plane such that when rotated slightly about its diameter and released, it starts performing simple harmonic motion of time period T . The mass of the loop is m then:

Question

A small circular loop of conducting wire has radius a and carries current I . It is placed in a uniform magnetic field B perpendicular to its plane such that when rotated slightly about its diameter and released, it starts performing simple harmonic motion of time period T . The mass of the loop is m then:, T = 2 m i B, T = π m 2 i B, T = 2 π m i B, T = π m i B

MARKS App · Accepted Answer

τ = M B sin ⁡ θ = I α π R 2 i B θ = m R 2 2 α ω = 2 π i B m = 2 π T ; T = 2 π m i B

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