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Question: Answered & Verified by Expert
A small cube of side of 1 mm is placed at the center of a circular loop of radius, 20 cm. If the current in the loop is, 2 A then the magnetic energy stored inside the cube is (Assume μ0=4π×10-7 SI units )
PhysicsElectromagnetic WavesTS EAMCETTS EAMCET 2021 (04 Aug Shift 2)
Options:
  • A 1.57×10-18 J
  • B 2.57×10-14 J
  • C 1.57×10-14 J
  • D 4.57×10-13 J
Solution:
1994 Upvotes Verified Answer
The correct answer is: 1.57×10-14 J

The formula of energy density in terms of strength of the magnetic field is, ud=12×B2μ0, then the energy of stored will be, u=ud×V=12×B2μ0×V, here the strength of the magnetic field can be calculated from the formula, B=μ0i2r

u=12×μ0i2r2μ0×a3u=4π×10-7220×10-22×10-33=1.57×10-14 J

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