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A small current carrying loop of area $A$ behaves like a tiny magnet of magnetic moment $M$. Current in the loop is
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Verified Answer
The correct answer is:
$M / A$
Magnetic moment of a coil of area A carrying current $I$ is given by
$\begin{aligned}
M &=I A \\
\Rightarrow \text { Current, } I &=\frac{M}{A}
\end{aligned}$
$\begin{aligned}
M &=I A \\
\Rightarrow \text { Current, } I &=\frac{M}{A}
\end{aligned}$
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