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Question: Answered & Verified by Expert
A small hole is made in a circular disc of mass ' $M$ ' and radius ' $R$ ' at a distance of $\frac{R}{4}$ from the centre. The disc is supported on a horizontal peg through this hole. The moment of inertia of the disc about the horizontal peg is
PhysicsRotational MotionAP EAMCETAP EAMCET 2017 (25 Apr Shift 2)
Options:
  • A $\frac{9 \mathrm{MR}^2}{16}$
  • B $\frac{5 \mathrm{MR}^2}{4}$
  • C $\frac{5 \mathrm{MR}^2}{16}$
  • D $\frac{\mathrm{MR}^2}{9}$
Solution:
2007 Upvotes Verified Answer
The correct answer is: $\frac{9 \mathrm{MR}^2}{16}$
No solution. Refer to answer key.

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