A small, metal wire loop is dragged across the gap between the poles of a magnet in 0.4 s . If the change in magnetic flux for the wire is 8 × 10 - 4 Wb , then the emf induced in the wire is

Question

A small, metal wire loop is dragged across the gap between the poles of a magnet in 0.4 s . If the change in magnetic flux for the wire is 8 × 10 - 4 Wb , then the emf induced in the wire is, 8 × 10 - 3 V, 6 × 10 - 3 V, 4 × 10 - 3 V, 2 × 10 - 3 V

MARKS App · Accepted Answer

e = dϕ dt = 8 × 10 - 4 0.4 = 2 × 10 - 3 V

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