A small smooth disc of mass m and radius r moving with an initial velocity v along the positive x -axis collided with a big disc of mass 2 m and radius 2 r which was initially at rest with its centre at origin as shown in the figure. If the coefficient of restitution is 0 , then the velocity of the larger disc after the collision is

Question

A small smooth disc of mass m and radius r moving with an initial velocity v along the positive x -axis collided with a big disc of mass 2 m and radius 2 r which was initially at rest with its centre at origin as shown in the figure. If the coefficient of restitution is 0 , then the velocity of the larger disc after the collision is, 8 27 v i ^ - 2 2 27 v j ^, 8 27 v i ^ - 2 27 v j ^, v 3 i ^, 2 2 27 v i ^ - 8 27 v j ^

MARKS App · Accepted Answer

The larger disc will move along line of impact As e = 0 , so velocity of larger disc v ′ = mv cos θ m + 2 m = v cos θ 3 Velocity of larger disc = v ' cos θ i ^ - v ' sin θ j ^ = v 3 cos 2 θ i ^ - v 3 sin θ cos θ j ^ ( from the figure we can calculate cos θ = 2 2 3 , sin θ = 1 3 ) = 8 27 v i ^ - 2 2 27 v j ^

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