A small sphere is given vertical velocity of magnitude v 0 = 5 m / s and it swings in a vertical plane about the end of the massless string. If maximum tension string can withstand is equal to twice of the weight of sphere, then angle θ with vertical at which string will break is

Question

A small sphere is given vertical velocity of magnitude v 0 = 5 m / s and it swings in a vertical plane about the end of the massless string. If maximum tension string can withstand is equal to twice of the weight of sphere, then angle θ with vertical at which string will break is, cos - 1 ⁡ 2 3, cos - 1 1 4, 60 °, 30 °

MARKS App · Accepted Answer

FBD of body at the position shown in diagram T – m g c o s θ = m v 2 l .....(i) Applying work energy theorem ⇒ m g l cos ⁡ θ = 1 2 m v 2 - 1 2 m v 0 2 ....(ii) T = 2 m g ......(iii) By solving ∴ cos ⁡ θ = 1 4

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