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A small telescope has an objective of focal length 140 cm and an eye piece of focal length 5.0 cm . The magnifying power of telescope for viewing a distant object is:
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Verified Answer
The correct answer is:
28
$f_0=140 \mathrm{~cm}$ and $f_e=5 \mathrm{~cm}$
For distant object,
$m=\frac{f_0}{f_e}=\frac{140}{5}=28$
For distant object,
$m=\frac{f_0}{f_e}=\frac{140}{5}=28$
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