Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A smooth sphere of mass M moving with velocity u directly collides elastically with another sphere of mass m at rest. After the collision, their final velocities are V and v respectively. Then v is
PhysicsCenter of Mass Momentum and CollisionJEE Main
Options:
  • A 2uMm
  • B 2umM
  • C 2u1+mM
  • D 2u1+Mm
Solution:
1431 Upvotes Verified Answer
The correct answer is: 2u1+mM
By law of conservation of momentum,

Mu=MV+mv…(i)
 e=|v1v2||u1u2|=v-Vue=1=v-Vuu=v-V
Mu=MvMV ....(ii)
From (i) and (ii), 2Mu=(M+m)v

v=2uMM+mv=2u1+mM

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.