A soap bubble has radius R and thickness d ( R ) as shown in the diagram. It collapses into a spherical drop. The ratio of excess pressure in the drop to the excess pressure inside the bubble is

Question

A soap bubble has radius R and thickness d ( R ) as shown in the diagram. It collapses into a spherical drop. The ratio of excess pressure in the drop to the excess pressure inside the bubble is, R 3 d 1 3, R 6 d 1 3, R 24 d 1 3, None of these

MARKS App · Accepted Answer

The volume of soap solution in a bubble = 4 π R 2 d now we make a drop 4 π R 2 d = 4 3 π r 3 ⇒ r = 3 R 2 d 1 / 3 Excess pressure initially = 4 S R Excess pressure finally = 2 S r = 2 S 3 R 2 d 1 / 3 Ratio = R 24 d 1 3

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