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A solenoid of inductance \( 2 \mathrm{H} \) carries a current of \( 1 \mathrm{~A} \). What is the magnetic energy stored in a
solenoid?
Options:
solenoid?
Solution:
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Verified Answer
The correct answer is:
\( 1 \mathrm{~J} \)
Energy stored in a solenoid is given as
\[
E=\frac{1}{2} L I^{2}
\]
Given, inductance of solenoid, \( \mathrm{L}=2 \mathrm{H} \); current in solenoid, \( \mathrm{I}=1 \mathrm{~A} \)
Therefore \( E=\frac{1}{2} \times 2 \times 1^{2}=1 \)
Thus, energy stored in solenoid = \( 1 \mathrm{~J} \)
\[
E=\frac{1}{2} L I^{2}
\]
Given, inductance of solenoid, \( \mathrm{L}=2 \mathrm{H} \); current in solenoid, \( \mathrm{I}=1 \mathrm{~A} \)
Therefore \( E=\frac{1}{2} \times 2 \times 1^{2}=1 \)
Thus, energy stored in solenoid = \( 1 \mathrm{~J} \)
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